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\def\calL{\mathcal{L}}
\def\calO{\mathcal{O}}
\def\calP{\mathcal{P}}
\def\calR{\mathcal{R}}
\def\calS{\mathcal{S}}
\def\calT{\mathcal{T}}
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\def\idb{\mathfrak{b}}
\def\idm{\mathfrak{m}}
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\def\idp{\mathfrak{p}}
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\def\PP{\mathbb{P}}
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\def\third{{\bf \noindent \newline Third Solution:  } \nopagebreak}
\def\fourth{{\bf \noindent \newline Fourth Solution:  } \nopagebreak}
\def\fifth{{\bf \noindent \newline Fifth Solution:  } \nopagebreak}
\def\sixth{{\bf \noindent \newline Sixth Solution:  } \nopagebreak}
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\def\comment{{\bf \noindent Comment:  } \nopagebreak}
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\pagestyle{empty}
\begin{document}
%\input epsf

\begin{center}
${\bf 33\rd}$ {\bf United States of America Mathematical Olympiad}
\end{center}



\begin{center}
{\bf  Day  II \hspace{ 6mm} 12:30 PM -- 5 PM}
\end{center}


\begin{center}
{\bf April 30, 2003}
\end{center}

\bigskip


\be
\setcounter{enumi}{3}
\ii %{\bf A\&F1}
Let $ABC$ be a triangle. A circle passing through $A$ and $B$
intersects  segments $AC$ and $BC$ at $D$ and $E$, respectively. Lines
$AB$ and $DE$ intersect at $F$ while lines $BD$ and $CF$ intersect at
$M$. Prove that $MF = MC$ if and only if $MB\cdot MD = MC^2$.

\vspace{5mm}

\ii %{\bf A\&F2}%T2 and ZF
Let $a, b, c$ be positive real numbers. Prove that
\[
\frac{(2a+b+c)^2}{2a^2+(b+c)^2} + \frac{(2b+c+a)^2}{2b^2+(c+a)^2} +
\frac{(2c+a+b)^2}{2c^2+(a+b)^2} \le 8.
\]

\vspace{5mm}

\ii %{\bf BAR3}
A positive integer is written at each vertex of a regular
hexagon so that the sum of all numbers written is $2003^{2003}$.
Bert makes a sequence of moves of the following form: Bert picks a
vertex and replaces the number written there by the absolute value
of the difference between the numbers written at the two
neighboring vertices. Prove that Bert can always make a sequence
of moves ending at the position with all six numbers equal to
zero.

\ee

\vfill
{\small
\begin{center}
Copyright \copyright \ \ Committee on the American  Mathematics
Competitions,\\
Mathematical Association of America
\end{center}
}

\end{document}

