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Mathematical Association of America -- American Mathematics Competitions

Math Club

2006 AMC 10A#18 - Interactive Problem

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Question

Question: 2006 AMC 10A #18
( A ) 104 • 262 ( B ) 103 • 263
( C ) 5 • 104 • 262
 ( D ) 102 • 264 ( E ) 5 • 103 • 263

 

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Solution

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